[gingery_machines] Re: Chord height Was new article: Making it Dead Flat and Square

 

Dick,

I may be calculating this wrong but I think your math is off. The curvature of the earth is about 1.5 inches in 1000 feet, therefore the chord height would be 0.75 inches not 0.1 inches.

Craig

--- In gingery_machines@yahoogroups.com, "R.L. Wurdack" <dickw@...> wrote:
>
> Water is not quite flat. For a 1000 foot chord, the diagonal of the base,
> the chord height due to the curvature of the Earth is nearly 0.1 inches. (1
> part in 120,000 - half the error budget for 1/8 inch in 700 feet.) The point
> I'm trying to make is that 1 part in 1000 is difficult, 1 part in 10000 is
> tough and 1 part in 100000 is messing with physics.
>
> Dick
> ----- Original Message -----
>

__._,_.___

Reply to sender | Reply to group | Reply via web post | Start a New Topic

Messages in this topic (5)

Recent Activity:

• New Members 9
• New Photos 16

Visit Your Group

<*> Member map - Who and where we are.  Please add yourself so members can find each other.
http://groups.yahoo.com/group/gingery_machines/app/peoplemap/view/map

Switch to: Text-Only, Daily Digest • Unsubscribe • Terms of Use

.

__,_._,___