Re: [gingery_machines] Re: Chord height Was new article: Making it Dead Flat and Square

 

Maybe so, I used a Mathematica function and I may have misused it - 0.75
would really make it ugly. Most calculators don't have enough precision in
their trig functions to do the math correctly.

D.

----- Original Message -----
From: "Craig Lundquist" <craigl2@earthlink.net>
To: <gingery_machines@yahoogroups.com>
Sent: Sunday, January 02, 2011 8:27 AM
Subject: [gingery_machines] Re: Chord height Was new article: Making it Dead
Flat and Square

> Dick,
>
> I may be calculating this wrong but I think your math is off. The
> curvature of the earth is about 1.5 inches in 1000 feet, therefore the
> chord height would be 0.75 inches not 0.1 inches.
>
> Craig
>
> --- In gingery_machines@yahoogroups.com, "R.L. Wurdack" <dickw@...> wrote:
>>
>> Water is not quite flat. For a 1000 foot chord, the diagonal of the base,
>> the chord height due to the curvature of the Earth is nearly 0.1 inches.
>> (1
>> part in 120,000 - half the error budget for 1/8 inch in 700 feet.) The
>> point
>> I'm trying to make is that 1 part in 1000 is difficult, 1 part in 10000
>> is
>> tough and 1 part in 100000 is messing with physics.
>>
>> Dick
>> ----- Original Message -----
>>
>
>
>
>
> ------------------------------------
>
> Yahoo! Groups Links
>
>
>
>

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